Have you looked at a bundle of many sheets of paper? How does it look? Does it look like what you see in Fig. 13.1?
That makes up a cuboid. How much of brown paper would you need, if you want to cover this cuboid? Let us see:
First we would need a rectangular piece to cover the bottom of the bundle. That would be as shown in Fig. 13.2 (a)
Then we would need two long rectangular pieces to cover the two side ends. Now, it would look like Fig. 13.2 (b).
\
Now to cover the front and back ends, we would need two more rectangular pieces of a different size. With them, we would now have a figure as shown in Fig. 13.2(c).
This figure, when opened out, would look like Fig. 13.2 (d).
Finally, to cover the top of the bundle, we would require another rectangular piece exactly like the one at the bottom, which if we attach on the right side, it would look like Fig. 13.2(e).
This shows us that the outer surface of a cuboid is made up of six rectangles (in fact, rectangular regions, called the faces of the cuboid), whose areas can be found by multiplying length by breadth for each of them separately and then adding the six areas together.
Now, if we take the length of the cuboid as l, breadth as b and the height as h, then the figure with these dimensions would be like the shape you see in Fig. 13.2(f).
So, the sum of the areas of the six rectangles is:
`color{green}("Area of rectangle" 1 (= l × h))`
`color{red}(text( +))`
`color{green}("Area of rectangle" 2 (= l × b))`
`color{red}(text( +))`
`color{green}("Area of rectangle" 3 (= l × h))`
`color{red}(text( +))`
`color{green}("Area of rectangle" 4 (= l × b))`
`color{red}(text( +))`
`color{green}("Area of rectangle" 5 (= b × h))`
`color{red}(text( +))`
`color{green}("Area of rectangle" 6 (= b × h))`
`color{blue}(= 2(l × b) + 2(b × h) + 2(l × h))`
`color{orange}(= 2(lb + bh + hl))`
This gives us:
`color{navy}("Surface Area of a Cuboid" = 2(lb + bh + hl))`
where l, b and h are respectively the three edges of the cuboid.
`ul"Note :"` The unit of area is taken as the square unit, because we measure the magnitude of a region by filling it with squares of side of unit length.
For example, if we have a cuboid whose length, breadth and height are 15 cm, 10 cm and 20 cm respectively, then its surface area would be:
`color{green}(2[(15 × 10) + (10 × 20) + (20 × 15)] cm^2)`
`color{orange}(= 2(150 + 200 + 300) cm^2)`
`color{blue}(= 2 × 650 cm^2)`
`color{red}(= 1300 cm^2)`
Recall that a cuboid, whose length, breadth and height are all equal, is called a cube. If each edge of the cube is a, then the surface area of this cube would be
`color{green}(2(a × a + a × a + a × a), i.e., 6a^2)` (see Fig. 13.3), giving us
`color{orange}("Surface Area of a Cube" = 6a^2)`
where a is the edge of the cube.
Suppose, out of the six faces of a cuboid, we only find the area of the four faces, leaving the bottom and top faces. In such a case, the area of these four faces is called the lateral surface area of the cuboid.
So, lateral surface area of a cuboid of length l, breadth b and height h is equal to `color{green}(2lh + 2bh or 2(l + b)h.)` Similarly, lateral surface area of a cube of side a is equal to `color{orange}(4a^2.)`
Keeping in view of the above, the surface area of a cuboid (or a cube) is sometimes also referred to as the total surface area. Let us now solve some examples.
Have you looked at a bundle of many sheets of paper? How does it look? Does it look like what you see in Fig. 13.1?
That makes up a cuboid. How much of brown paper would you need, if you want to cover this cuboid? Let us see:
First we would need a rectangular piece to cover the bottom of the bundle. That would be as shown in Fig. 13.2 (a)
Then we would need two long rectangular pieces to cover the two side ends. Now, it would look like Fig. 13.2 (b).
\
Now to cover the front and back ends, we would need two more rectangular pieces of a different size. With them, we would now have a figure as shown in Fig. 13.2(c).
This figure, when opened out, would look like Fig. 13.2 (d).
Finally, to cover the top of the bundle, we would require another rectangular piece exactly like the one at the bottom, which if we attach on the right side, it would look like Fig. 13.2(e).
This shows us that the outer surface of a cuboid is made up of six rectangles (in fact, rectangular regions, called the faces of the cuboid), whose areas can be found by multiplying length by breadth for each of them separately and then adding the six areas together.
Now, if we take the length of the cuboid as l, breadth as b and the height as h, then the figure with these dimensions would be like the shape you see in Fig. 13.2(f).
So, the sum of the areas of the six rectangles is:
`color{green}("Area of rectangle" 1 (= l × h))`
`color{red}(text( +))`
`color{green}("Area of rectangle" 2 (= l × b))`
`color{red}(text( +))`
`color{green}("Area of rectangle" 3 (= l × h))`
`color{red}(text( +))`
`color{green}("Area of rectangle" 4 (= l × b))`
`color{red}(text( +))`
`color{green}("Area of rectangle" 5 (= b × h))`
`color{red}(text( +))`
`color{green}("Area of rectangle" 6 (= b × h))`
`color{blue}(= 2(l × b) + 2(b × h) + 2(l × h))`
`color{orange}(= 2(lb + bh + hl))`
This gives us:
`color{navy}("Surface Area of a Cuboid" = 2(lb + bh + hl))`
where l, b and h are respectively the three edges of the cuboid.
`ul"Note :"` The unit of area is taken as the square unit, because we measure the magnitude of a region by filling it with squares of side of unit length.
For example, if we have a cuboid whose length, breadth and height are 15 cm, 10 cm and 20 cm respectively, then its surface area would be:
`color{green}(2[(15 × 10) + (10 × 20) + (20 × 15)] cm^2)`
`color{orange}(= 2(150 + 200 + 300) cm^2)`
`color{blue}(= 2 × 650 cm^2)`
`color{red}(= 1300 cm^2)`
Recall that a cuboid, whose length, breadth and height are all equal, is called a cube. If each edge of the cube is a, then the surface area of this cube would be
`color{green}(2(a × a + a × a + a × a), i.e., 6a^2)` (see Fig. 13.3), giving us
`color{orange}("Surface Area of a Cube" = 6a^2)`
where a is the edge of the cube.
Suppose, out of the six faces of a cuboid, we only find the area of the four faces, leaving the bottom and top faces. In such a case, the area of these four faces is called the lateral surface area of the cuboid.
So, lateral surface area of a cuboid of length l, breadth b and height h is equal to `color{green}(2lh + 2bh or 2(l + b)h.)` Similarly, lateral surface area of a cube of side a is equal to `color{orange}(4a^2.)`
Keeping in view of the above, the surface area of a cuboid (or a cube) is sometimes also referred to as the total surface area. Let us now solve some examples.